import java.io.*;
class SortIntArrayIt4
{

 public static void main(String[] args)
 throws IOException
 // Illustrates use of recursion to read a number of integers into
 // an array, without specifying how many in advance
 {
  int n;
  int[] array;
  BufferedReader in = new BufferedReader(new InputStreamReader(System.in));
  array = readInts(0,in);
  System.out.println("The array you entered is:");
  System.out.println(arrayToString(array));
  sort(array);
  System.out.println("After sorting, the array is:");
  System.out.println(arrayToString(array));
 }

 public static int[] readInts(int count,BufferedReader in)
 throws IOException
 {
  System.out.print("Enter integer "+count+" or new line to halt: ");
  String line=in.readLine();
  if(line.equals(""))
     return new int[count];
  else
     {
      int n = Integer.parseInt(line);
      int[] a = readInts(count+1,in);
      a[count]=n;
      return a;
     }
 }

 private static String arrayToString(int[] a)
 {
  String str="[";
  if(a.length>0)
     {
      str+=a[0];
      for(int i=1; i<a.length; i++)
         str+="|"+a[i];
     }
  return str+"]";
 }

 public static void sort(int[] a)
 // Sort the contents of array a in ascending numerical order
 {
  for(int i=0; i<a.length-1; i++)
     {
      int temp,pos=i;
      for(int j=i+1; j<a.length; j++)
         if(a[j]<a[pos])
            pos=j;
      temp = a[i];
      a[i] = a[pos];
      a[pos] = temp;
     }
 }

}